Question

Give the excluded values for 3/8m + 7/m+4 = m+1/m-16
. Do not solve.

Answer 1

To find the excluded values for the equation

\[
\frac{3}{8m} + \frac{7}{m+4} = \frac{m+1}{m-16},
\]

we need to identify values of \( m \) that would make any denominator equal to zero, as these values would make the expression undefined.

1. The denominator \( 8m \) is zero when:
\[
8m = 0 \implies m = 0.
\]

2. The denominator \( m + 4 \) is zero when:
\[
m + 4 = 0 \implies m = -4.
\]

3. The denominator \( m - 16 \) is zero when:
\[
m - 16 = 0 \implies m = 16.
\]

Therefore, the excluded values are \( m = 0, m = -4, \) and \( m = 16 \).