Question
At a certain food truck, hot dogs cost $3
and burgers cost $5
. A customer ordered 7
items and spent $27
.
) If x
is the number of burgers the customer bought and y
is the number of hot dogs, write a system of equations that models the problem and graph it.
) How many of each item were purchased?
and burgers cost $5
. A customer ordered 7
items and spent $27
.
) If x
is the number of burgers the customer bought and y
is the number of hot dogs, write a system of equations that models the problem and graph it.
) How many of each item were purchased?
Answers
GPT-4o mini
To model the problem using a system of equations, we have two types of items (burgers and hot dogs) and two constraints given by the problem (the total number of items and the total cost).
Let:
- \( x \) be the number of burgers
- \( y \) be the number of hot dogs
From the problem, we can form the following equations:
1. The total number of items equation:
\[
x + y = 7
\]
2. The total cost equation:
\[
5x + 3y = 27
\]
Now, we have the system of equations:
\[
\begin{align*}
1. & \quad x + y = 7 \quad \text{(1)} \\
2. & \quad 5x + 3y = 27 \quad \text{(2)}
\end{align*}
\]
### Solving the System of Equations
We can solve this system using substitution or elimination. Let's use substitution by solving equation (1) for \( y \):
\[
y = 7 - x
\]
Now, we can substitute \( y \) in equation (2):
\[
5x + 3(7 - x) = 27
\]
Expanding and simplifying:
\[
5x + 21 - 3x = 27
\]
\[
2x + 21 = 27
\]
Subtracting 21 from both sides:
\[
2x = 6
\]
Dividing by 2:
\[
x = 3
\]
Now plug \( x \) back into equation (1) to find \( y \):
\[
3 + y = 7
\]
Subtracting 3 from both sides:
\[
y = 4
\]
### Conclusion
The customer purchased:
- 3 burgers
- 4 hot dogs
### Verification of the Solution
To verify, we can check both equations with \( x = 3 \) and \( y = 4 \):
1. \( x + y = 7 \):
\[
3 + 4 = 7 \quad \text{(True)}
\]
2. \( 5x + 3y = 27 \):
\[
5(3) + 3(4) = 15 + 12 = 27 \quad \text{(True)}
\]
Both equations are satisfied, confirming that the solutions are correct.
Let:
- \( x \) be the number of burgers
- \( y \) be the number of hot dogs
From the problem, we can form the following equations:
1. The total number of items equation:
\[
x + y = 7
\]
2. The total cost equation:
\[
5x + 3y = 27
\]
Now, we have the system of equations:
\[
\begin{align*}
1. & \quad x + y = 7 \quad \text{(1)} \\
2. & \quad 5x + 3y = 27 \quad \text{(2)}
\end{align*}
\]
### Solving the System of Equations
We can solve this system using substitution or elimination. Let's use substitution by solving equation (1) for \( y \):
\[
y = 7 - x
\]
Now, we can substitute \( y \) in equation (2):
\[
5x + 3(7 - x) = 27
\]
Expanding and simplifying:
\[
5x + 21 - 3x = 27
\]
\[
2x + 21 = 27
\]
Subtracting 21 from both sides:
\[
2x = 6
\]
Dividing by 2:
\[
x = 3
\]
Now plug \( x \) back into equation (1) to find \( y \):
\[
3 + y = 7
\]
Subtracting 3 from both sides:
\[
y = 4
\]
### Conclusion
The customer purchased:
- 3 burgers
- 4 hot dogs
### Verification of the Solution
To verify, we can check both equations with \( x = 3 \) and \( y = 4 \):
1. \( x + y = 7 \):
\[
3 + 4 = 7 \quad \text{(True)}
\]
2. \( 5x + 3y = 27 \):
\[
5(3) + 3(4) = 15 + 12 = 27 \quad \text{(True)}
\]
Both equations are satisfied, confirming that the solutions are correct.