translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ? (1 point) Responses (10, 4) left parenthesis 10 comma 4 right parenthesis (2, 0) left parenthesis 2 comma 0 right parenthesis (6, 0) left parenthesis 6 comma 0 right parenthesis (2, 12)

Answer 1

To translate point P down 6 units and to the right 2 units, we need to adjust its coordinates accordingly.

Let's denote the original coordinates of point P as \( (x, y) \).

1. Translate down 6 units: This means we subtract 6 from the y-coordinate. \( y' = y - 6 \)

2. Translate right 2 units: This means we add 2 to the x-coordinate. \( x' = x + 2 \)

Therefore, the new coordinates \( P' \) will be:

• \( P' = (x + 2, y - 6) \)

To find the specific coordinates of \( P' \), we need the original coordinates of point P, which you've not provided. Please provide the coordinates of point P for an exact answer.

However, if we assume \( P \) is at an example point such as \( (0, 0) \):

• \( P' = (0 + 2, 0 - 6) = (2, -6) \)

But if \( P \) is at one of the provided option points, we can determine it accordingly.

So please specify or clarify the coordinates of point P, and I can assist you further!