Qc = same as Kc for this.
Kc = (product)^x(product)^y/(reactant)^z
where x, y, and z are the coefficients in the balanced equation.
In words it goes like this. The product of the products of a reaction divided by the product of the reactants, each raised to a power indicated by the coefficients in the balanced chemical equation, is a constant. This is called the equilibrium constant. [In this case it is the "reaction quotient".]
I don't like B.
Qc for the following chemical reaction
3CIO2-(aq)<-->2CIO3-(aq)+Cl-(aq)
Choices
A:3[CIO2-]/2[CIO3-][Cl}
B:2[CIO3-][Cl]/3[CIO2-]
C:[CIO2-]^3/[CIO3-]^2[Cl-]
D:[CIO3-]^2[Cl-]/[CIO2-]^3
I like B: what would you go for??
thanks all
7 answers
Dr Bob
I don't like B or C or D
that only leaves A
Is this what you would go for ????
Thanks andy
I don't like B or C or D
that only leaves A
Is this what you would go for ????
Thanks andy
Do what the words say do. Do what my equation says to do.
Aha its actually A???
Correct???
Correct???
You must be guessing. The answer is D.
If you followed my equation OR the words I wrote, you would KNOW it is D.
The product of the products of the reaction, divided by the product of the reactants (that eliminates A and C because the reactants are the numerator), each raised to a power indicated......etc (that eliminates B because those are coefficients and not exponents. It MUST be between C and D because those are the ONLY two that use exponents and it can't be C because the reactants are in the numerator and the products are in the denominator.
If you followed my equation OR the words I wrote, you would KNOW it is D.
The product of the products of the reaction, divided by the product of the reactants (that eliminates A and C because the reactants are the numerator), each raised to a power indicated......etc (that eliminates B because those are coefficients and not exponents. It MUST be between C and D because those are the ONLY two that use exponents and it can't be C because the reactants are in the numerator and the products are in the denominator.
Oh I see now that you explained it that way!!!!
OOPS....sorry yes I took a stab in the dark.....One day I may get this stuff....its going to be a long trip....How do YOU remember all this???
My heads about to explode and I am too young to die!!!!!!!!
OOPS....sorry yes I took a stab in the dark.....One day I may get this stuff....its going to be a long trip....How do YOU remember all this???
My heads about to explode and I am too young to die!!!!!!!!
The words I quoted above are the EXACT words my freshman chemistry professor used to explain Keq 62 years ago. I can remember all of that stuff I learned years ago---it's the recent stuff I have trouble with. I work a problem today with new information and forget tomorrow how I did it and must do it again from scratch.