To find the vertex of the quadratic function \( h(t) = -6t^2 - 24t + 20 \), we can use the vertex formula for a quadratic function given in the standard form \( ax^2 + bx + c \). The t-coordinate of the vertex can be found using the formula:
\[ t = -\frac{b}{2a} \]
In our case:
- \( a = -6 \)
- \( b = -24 \)
Now, substituting in the values:
\[ t = -\frac{-24}{2 \times -6} = \frac{24}{-12} = -2 \]
Next, we substitute \( t = -2 \) back into the function \( h(t) \) to find the corresponding height \( h \):
\[ h(-2) = -6(-2)^2 - 24(-2) + 20 \] \[ h(-2) = -6(4) + 48 + 20 \] \[ h(-2) = -24 + 48 + 20 \] \[ h(-2) = 24 \]
Thus, the vertex of the parabola is the point \( (-2, 24) \).
However, none of the ordered pairs in the provided responses match this vertex, indicating there may be an error in the question's options. Despite this, we correctly calculated that the vertex is \( (-2, 24) \). If you require further clarification or assistance, please let me know!