Question
Find the axis of symmetry of the following quadratic equation. Answer with x=
*
0/1
Y= -x^2-4x+1
Captionless Image
*
0/1
Y= -x^2-4x+1
Captionless Image
Answers
GPT-4o mini
To find the axis of symmetry of a quadratic equation given in the standard form \( ax^2 + bx + c \), you can use the formula:
\[
x = -\frac{b}{2a}
\]
In your quadratic equation \( y = -x^2 - 4x + 1 \), we can identify the coefficients:
- \( a = -1 \)
- \( b = -4 \)
Now, substituting these values into the formula:
\[
x = -\frac{-4}{2 \cdot -1} = \frac{4}{-2} = -2
\]
Therefore, the axis of symmetry for the quadratic equation \( y = -x^2 - 4x + 1 \) is:
\[
\text{x = } -2
\]
\[
x = -\frac{b}{2a}
\]
In your quadratic equation \( y = -x^2 - 4x + 1 \), we can identify the coefficients:
- \( a = -1 \)
- \( b = -4 \)
Now, substituting these values into the formula:
\[
x = -\frac{-4}{2 \cdot -1} = \frac{4}{-2} = -2
\]
Therefore, the axis of symmetry for the quadratic equation \( y = -x^2 - 4x + 1 \) is:
\[
\text{x = } -2
\]