To solve the problem, we can use a Punnett square to determine the genotypes of the offspring from the crosses.
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Initial Cross: Mitchell is crossing a homozygous purple snapdragon (PP) with a homozygous white snapdragon (ww).
- The possible gametes from the PP parent are all P (since it is homozygous).
- The possible gametes from the ww parent are all w (since it is also homozygous).
Therefore, when we make the cross:
\[ \begin{array}{|c|c|c|} \hline & P & P \ \hline w & Pw & Pw \ \hline w & Pw & Pw \ \hline \end{array} \]
All first-generation offspring (F1) will have the genotype Pw, which are all purple flowers since purple (P) is dominant over white (w).
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Second Generation Cross: Now, Mitchell breeds two of the F1 offspring together (Pw x Pw):
- The possible gametes from each Pw parent are P and w.
To find the genotypes of the F2 generation, we make another Punnett square:
\[ \begin{array}{|c|c|c|} \hline & P & w \ \hline P & PP & Pw \ \hline w & Pw & ww \ \hline \end{array} \]
From this Punnett square, we can see the genotypes of the F2 generation:
- PP (purple)
- Pw (purple)
- Pw (purple)
- ww (white)
The ratios of the genotypes are:
- 1 PP
- 2 Pw
- 1 ww
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Calculating Percentages: Out of a total of 4 offspring (1 PP + 2 Pw + 1 ww), 1 offspring is white (ww).
Therefore, the percentage of the second generation offspring that will most likely be white is:
\[ \frac{1 \text{ (ww)} }{4 \text{ (total)}} \times 100% = 25% \]
The answer is a 25%.