there are 2 tyes of tickets to attend an awards dinner---so;ver and gold. The gold tickets are $8 more than the silver. If Patrick bought 10 tickets at each level and spent a total of $140, Find the price of each ticket.

Question

4__ ofr each solver ticket and $__ for each gold ticket

Answer 1

Let the price of the silver ticket be \( x \) dollars. Then, the price of the gold ticket would be \( x + 8 \) dollars.

Patrick bought 10 silver tickets and 10 gold tickets. The total cost can be expressed as:

\[ 10(x) + 10(x + 8) = 140 \]

Now simplify the equation:

\[ 10x + 10(x + 8) = 140 \] \[ 10x + 10x + 80 = 140 \] \[ 20x + 80 = 140 \]

Now, subtract 80 from both sides:

\[ 20x = 60 \]

Now, divide by 20:

\[ x = 3 \]

So, the price of the silver ticket is \( x = 3 \) dollars. The price of the gold ticket would be:

\[ x + 8 = 3 + 8 = 11 \text{ dollars} \]

Thus, the prices are:

• Silver ticket: $3
• Gold ticket: $11