Using a formula for a binomial proportion one-sample z-test with your data included, we have:
z = .55 - .50 / √[(.50)(.50)/500] -->note: .55 is 275/500 in decimal form.
Finish the calculation.
Use a z-table to find the critical or cutoff value at 0.05 for a one-tailed test.
If the z-test statistic calculated above exceeds the critical value from the z-table, reject the null. If the z-test statistic does not exceed the critical value from the z-table, do not reject the null.
I hope this will help get you started.
A usu today survey foudn that of the gun owners surveyed 275 favor sticter gun laws. The survey involved 500 gun owners. Test the claim that a mojority( more than 50%) of gun owners favor stricter fun laws. use .05 significane level
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