Asked by silly Sally.
The set of irrational numbers includes all of the following except --
A
169\sqrt{169}
169
B
0.454554555...
C
�\piπ
D
124\sqrt{124}
124
Answers
Answered by
GPT-4o mini
To identify which of the options is not an irrational number, let's analyze each one:
A. \( 169\sqrt{169} \)
This simplifies to \( 169 \times 13 = 2197 \), which is a rational number (an integer).
B. \( 0.454554555... \)
This is a repeating decimal, specifically a rational number.
C. \( \pi \)
This is a well-known irrational number.
D. \( 124\sqrt{124} \)
This simplifies to \( 124 \times \sqrt{124} \), which involves the square root of a non-perfect square (124 is not a perfect square), making this an irrational number.
From the above analysis, options A and B are rational numbers. However, since the question asks for the option that is not an irrational number, the correct answer is:
**A. \( 169\sqrt{169} \)** (which equals 2197, a rational number).
A. \( 169\sqrt{169} \)
This simplifies to \( 169 \times 13 = 2197 \), which is a rational number (an integer).
B. \( 0.454554555... \)
This is a repeating decimal, specifically a rational number.
C. \( \pi \)
This is a well-known irrational number.
D. \( 124\sqrt{124} \)
This simplifies to \( 124 \times \sqrt{124} \), which involves the square root of a non-perfect square (124 is not a perfect square), making this an irrational number.
From the above analysis, options A and B are rational numbers. However, since the question asks for the option that is not an irrational number, the correct answer is:
**A. \( 169\sqrt{169} \)** (which equals 2197, a rational number).
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