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using a deck of cards,what is the probability that you would pull a red kind and a black queen in two pulls without replacing t...Asked by kezia
using a deck of cards,what is the probability that you would pull a red kind and a black queen in two pulls without replacing the first card back into the deck?
Answers
Answered by
drwls
I believe you mean read KING, not red KIND. There are two red kings and two black queens. The probability of drawing either one, in a single draw, is 2/52 = 1/26.
There are two ways you could end up with one black queen and one red king: You could get the king first or the queen first. The total probability is
2*(1/26)^2 = 1/338
There are two ways you could end up with one black queen and one red king: You could get the king first or the queen first. The total probability is
2*(1/26)^2 = 1/338
Answered by
Reiny
Since you are not replacing the card, the prob of the second draw is different from the first draw.
could be RK,BQ or BW,RK
prob of that is (2/52)(2/51) + (2/52)(2/51)
= 2(2/52)(2/51) = 2/663
or
choose a red king -->C(4,2) = 2
choose a black queen --> C(4,2) = 2
choose any two cards --> C(52,2) = 1326
prob = 2*2/1326 = 2/663
could be RK,BQ or BW,RK
prob of that is (2/52)(2/51) + (2/52)(2/51)
= 2(2/52)(2/51) = 2/663
or
choose a red king -->C(4,2) = 2
choose a black queen --> C(4,2) = 2
choose any two cards --> C(52,2) = 1326
prob = 2*2/1326 = 2/663
Answered by
drwls
Reiny is correct; I missed the word "without" (replacing).
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