volume
= π[inegral] (e^(5x) + 3)^2 dx from 0 to .8
= π[integral] (e^(10x) + 6e^(5x) + 9) dx
= π [ (1/10)e^(10x) + (6/5)e^(5x) + 9x] from 0 to .8
= π((1/10)e^8 + (6/5)e^4 + 7.2 - ((1/10)(1) + 6/5 + 0))
= ...
I will let you finish the "button-pushing"
Find the volume of the solid formed by rotating the region enclosed by
y=e^(5x)+(3), y=0, x=0, x=0.8 about the x-axis.
1 answer