Question
A rectangle has a width of x−1
𝑥
−
1
inches and a length of 3x
3
𝑥
inches. Find the values of x that will produce a rectangle that has an area greater than 18 square inches.(1 point)
Responses
all values of x such that x>3
𝑥
>
3
all values of x such that x is greater than 3 - no response given
all values of x such that x<−3
𝑥
<
−
3
or x>2
𝑥
>
2
all values of x such that x<−3
𝑥
<
−
3
or x is greater than 2 - incorrect
all values of x such that x>2
𝑥
>
2
all values of x such that x is greater than 2 - no response given
all values of x such that x<−2
𝑥
<
−
2
or x>3
𝑥
−
1
inches and a length of 3x
3
𝑥
inches. Find the values of x that will produce a rectangle that has an area greater than 18 square inches.(1 point)
Responses
all values of x such that x>3
𝑥
>
3
all values of x such that x is greater than 3 - no response given
all values of x such that x<−3
𝑥
<
−
3
or x>2
𝑥
>
2
all values of x such that x<−3
𝑥
<
−
3
or x is greater than 2 - incorrect
all values of x such that x>2
𝑥
>
2
all values of x such that x is greater than 2 - no response given
all values of x such that x<−2
𝑥
<
−
2
or x>3
Answers
Answered by
GPT-4o mini
To find the values of \( x \) that will produce a rectangle with an area greater than 18 square inches, we can start by calculating the area \( A \) of the rectangle using the given dimensions:
- Width: \( x - 1 \)
- Length: \( 3x \)
The area \( A \) is given by:
\[
A = \text{Width} \times \text{Length} = (x - 1)(3x)
\]
Expanding this expression:
\[
A = 3x(x - 1) = 3x^2 - 3x
\]
We want to find when this area is greater than 18 square inches:
\[
3x^2 - 3x > 18
\]
To solve this inequality, we first rearrange it:
\[
3x^2 - 3x - 18 > 0
\]
Next, we can simplify it by dividing everything by 3:
\[
x^2 - x - 6 > 0
\]
Now, we can factor the quadratic expression:
\[
(x - 3)(x + 2) > 0
\]
Now we will determine the critical points by setting the factors equal to zero:
1. \( x - 3 = 0 \Rightarrow x = 3 \)
2. \( x + 2 = 0 \Rightarrow x = -2 \)
These critical points divide the number line into intervals. We will test the intervals to see where the product is positive:
1. Interval \( (-\infty, -2) \):
- Choose \( x = -3 \): \(( -3 - 3)( -3 + 2) = (-6)(-1) > 0\) (True)
2. Interval \( (-2, 3) \):
- Choose \( x = 0 \): \((0 - 3)(0 + 2) = (-3)(2) < 0\) (False)
3. Interval \( (3, \infty) \):
- Choose \( x = 4 \): \((4 - 3)(4 + 2) = (1)(6) > 0\) (True)
So the solution to the inequality \( (x - 3)(x + 2) > 0 \) is:
\[
x < -2 \quad \text{or} \quad x > 3
\]
Thus, the values of \( x \) that will produce a rectangle with an area greater than 18 square inches are all values of \( x \) such that:
\[
x < -2 \quad \text{or} \quad x > 3
\]
Given the provided choices, the correct response would be: **all values of x such that \( x < -2 \) or \( x > 3 \)**.
- Width: \( x - 1 \)
- Length: \( 3x \)
The area \( A \) is given by:
\[
A = \text{Width} \times \text{Length} = (x - 1)(3x)
\]
Expanding this expression:
\[
A = 3x(x - 1) = 3x^2 - 3x
\]
We want to find when this area is greater than 18 square inches:
\[
3x^2 - 3x > 18
\]
To solve this inequality, we first rearrange it:
\[
3x^2 - 3x - 18 > 0
\]
Next, we can simplify it by dividing everything by 3:
\[
x^2 - x - 6 > 0
\]
Now, we can factor the quadratic expression:
\[
(x - 3)(x + 2) > 0
\]
Now we will determine the critical points by setting the factors equal to zero:
1. \( x - 3 = 0 \Rightarrow x = 3 \)
2. \( x + 2 = 0 \Rightarrow x = -2 \)
These critical points divide the number line into intervals. We will test the intervals to see where the product is positive:
1. Interval \( (-\infty, -2) \):
- Choose \( x = -3 \): \(( -3 - 3)( -3 + 2) = (-6)(-1) > 0\) (True)
2. Interval \( (-2, 3) \):
- Choose \( x = 0 \): \((0 - 3)(0 + 2) = (-3)(2) < 0\) (False)
3. Interval \( (3, \infty) \):
- Choose \( x = 4 \): \((4 - 3)(4 + 2) = (1)(6) > 0\) (True)
So the solution to the inequality \( (x - 3)(x + 2) > 0 \) is:
\[
x < -2 \quad \text{or} \quad x > 3
\]
Thus, the values of \( x \) that will produce a rectangle with an area greater than 18 square inches are all values of \( x \) such that:
\[
x < -2 \quad \text{or} \quad x > 3
\]
Given the provided choices, the correct response would be: **all values of x such that \( x < -2 \) or \( x > 3 \)**.
There are no human answers yet. A form for humans to post answers is coming very soon!