Question
Based on past experience, a bank believes that 8 % of the people who receive loans will not make payments on time. The bank has recently approved 200 loans.
What are the mean and standard deviation of this model?
What are the mean and standard deviation of this model?
Answers
GPT-4o mini
To solve this problem, we can model the situation using a binomial distribution since we are dealing with a fixed number of trials (loans), each with two possible outcomes (making payments on time or not).
Let:
- \( n \) = number of trials (loans approved) = 200
- \( p \) = probability of success (not making payments on time) = 0.08
- \( q \) = probability of failure (making payments on time) = \( 1 - p = 0.92 \)
### Mean
The mean \( \mu \) of a binomial distribution can be calculated using the formula:
\[
\mu = n \cdot p
\]
Substituting in the values:
\[
\mu = 200 \cdot 0.08 = 16
\]
### Standard Deviation
The standard deviation \( \sigma \) of a binomial distribution can be calculated using the formula:
\[
\sigma = \sqrt{n \cdot p \cdot q}
\]
Substituting in the values:
\[
\sigma = \sqrt{200 \cdot 0.08 \cdot 0.92}
\]
\[
\sigma = \sqrt{200 \cdot 0.0736} \approx \sqrt{14.72} \approx 3.84
\]
### Conclusion
Thus, the mean number of people who will not make payments on time is \( 16 \), and the standard deviation is approximately \( 3.84 \).
Let:
- \( n \) = number of trials (loans approved) = 200
- \( p \) = probability of success (not making payments on time) = 0.08
- \( q \) = probability of failure (making payments on time) = \( 1 - p = 0.92 \)
### Mean
The mean \( \mu \) of a binomial distribution can be calculated using the formula:
\[
\mu = n \cdot p
\]
Substituting in the values:
\[
\mu = 200 \cdot 0.08 = 16
\]
### Standard Deviation
The standard deviation \( \sigma \) of a binomial distribution can be calculated using the formula:
\[
\sigma = \sqrt{n \cdot p \cdot q}
\]
Substituting in the values:
\[
\sigma = \sqrt{200 \cdot 0.08 \cdot 0.92}
\]
\[
\sigma = \sqrt{200 \cdot 0.0736} \approx \sqrt{14.72} \approx 3.84
\]
### Conclusion
Thus, the mean number of people who will not make payments on time is \( 16 \), and the standard deviation is approximately \( 3.84 \).