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Ava wrote the expression 4−1/2−3 to determine the slope of a line. Which table might represent Ava’s line?(1 point) Responses a...Question
Ava wrote the expression (4−1)/(2−3)
to determine the slope of a line. Which table might represent Ava’s line?(1 point)
Responses
x y
3 4
-1 -2
x y
4 3
2 1
x y
3 1
2 4
x y
4 3
2 1
to determine the slope of a line. Which table might represent Ava’s line?(1 point)
Responses
x y
3 4
-1 -2
x y
4 3
2 1
x y
3 1
2 4
x y
4 3
2 1
Answers
Answered by
GPT-4o mini
To determine the slope from Ava's expression \((4−1)/(2−3)\), we can simplify the expression:
\[
\frac{4 - 1}{2 - 3} = \frac{3}{-1} = -3
\]
The slope of the line is \(-3\).
Now, to find a table that represents a line with a slope of \(-3\), we will check if we can find two points in one of the tables that have a slope of \(-3\). The slope \(-3\) means that for every 1 unit increase in \(x\), \(y\) will decrease by 3 units.
Let's examine the provided tables:
1. Table:
\[
\begin{array}{c|c}
x & y \\
\hline
3 & 4 \\
-1 & -2 \\
\end{array}
\]
The slope between (3, 4) and (-1, -2) is:
\[
\text{slope} = \frac{-2 - 4}{-1 - 3} = \frac{-6}{-4} = \frac{3}{2} \quad \text{(not -3)}
\]
2. Table:
\[
\begin{array}{c|c}
x & y \\
\hline
4 & 3 \\
2 & 1 \\
\end{array}
\]
The slope between (4, 3) and (2, 1) is:
\[
\text{slope} = \frac{1 - 3}{2 - 4} = \frac{-2}{-2} = 1 \quad \text{(not -3)}
\]
3. Table:
\[
\begin{array}{c|c}
x & y \\
\hline
3 & 1 \\
2 & 4 \\
\end{array}
\]
The slope between (3, 1) and (2, 4) is:
\[
\text{slope} = \frac{4 - 1}{2 - 3} = \frac{3}{-1} = -3 \quad \text{(correct)}
\]
4. (Duplicate of the second table given previously)
The table that represents Ava's line with a slope of \(-3\) is:
\[
\begin{array}{c|c}
x & y \\
\hline
3 & 1 \\
2 & 4 \\
\end{array}
\]
So the answer is the third table.
\[
\frac{4 - 1}{2 - 3} = \frac{3}{-1} = -3
\]
The slope of the line is \(-3\).
Now, to find a table that represents a line with a slope of \(-3\), we will check if we can find two points in one of the tables that have a slope of \(-3\). The slope \(-3\) means that for every 1 unit increase in \(x\), \(y\) will decrease by 3 units.
Let's examine the provided tables:
1. Table:
\[
\begin{array}{c|c}
x & y \\
\hline
3 & 4 \\
-1 & -2 \\
\end{array}
\]
The slope between (3, 4) and (-1, -2) is:
\[
\text{slope} = \frac{-2 - 4}{-1 - 3} = \frac{-6}{-4} = \frac{3}{2} \quad \text{(not -3)}
\]
2. Table:
\[
\begin{array}{c|c}
x & y \\
\hline
4 & 3 \\
2 & 1 \\
\end{array}
\]
The slope between (4, 3) and (2, 1) is:
\[
\text{slope} = \frac{1 - 3}{2 - 4} = \frac{-2}{-2} = 1 \quad \text{(not -3)}
\]
3. Table:
\[
\begin{array}{c|c}
x & y \\
\hline
3 & 1 \\
2 & 4 \\
\end{array}
\]
The slope between (3, 1) and (2, 4) is:
\[
\text{slope} = \frac{4 - 1}{2 - 3} = \frac{3}{-1} = -3 \quad \text{(correct)}
\]
4. (Duplicate of the second table given previously)
The table that represents Ava's line with a slope of \(-3\) is:
\[
\begin{array}{c|c}
x & y \\
\hline
3 & 1 \\
2 & 4 \\
\end{array}
\]
So the answer is the third table.
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