Asked by hbhjgjh
a dog groomer charges her clients by the weight of the dog. the following peicewise function represents the total charge, f(x), for a dog weighing x pounds
Answers
Answered by
GPT-4o mini
It seems like you're looking to describe a piecewise function for the charges that a dog groomer applies based on the weight of the dog. Here's an example of how such a function might be structured:
Let's say the groomer has the following pricing:
- For dogs weighing 0 to 10 pounds: \( f(x) = 20 \) (a flat fee)
- For dogs weighing 11 to 30 pounds: \( f(x) = 20 + 1.50(x - 10) \) (base fee plus an additional $1.50 per pound over 10)
- For dogs weighing 31 to 50 pounds: \( f(x) = 20 + 30 + 1.00(x - 30) \) (if the dog weighs more than 30 pounds, it includes the previous charges plus $1.00 per pound over 30)
- For dogs over 50 pounds: \( f(x) = 50 + 0.80(x - 50) \) (if the dog exceeds 50 pounds, it adds $0.80 for each pound over 50)
Now, we can define the piecewise function more formally:
\[
f(x) =
\begin{cases}
20 & \text{if } 0 < x \leq 10 \\
20 + 1.50(x - 10) & \text{if } 10 < x \leq 30 \\
50 + 1.00(x - 30) & \text{if } 30 < x \leq 50 \\
80 + 0.80(x - 50) & \text{if } x > 50
\end{cases}
\]
Make sure to adjust the specific numbers and slopes according to the actual pricing of your dog grooming. Let me know if you'd like further assistance with this!
Let's say the groomer has the following pricing:
- For dogs weighing 0 to 10 pounds: \( f(x) = 20 \) (a flat fee)
- For dogs weighing 11 to 30 pounds: \( f(x) = 20 + 1.50(x - 10) \) (base fee plus an additional $1.50 per pound over 10)
- For dogs weighing 31 to 50 pounds: \( f(x) = 20 + 30 + 1.00(x - 30) \) (if the dog weighs more than 30 pounds, it includes the previous charges plus $1.00 per pound over 30)
- For dogs over 50 pounds: \( f(x) = 50 + 0.80(x - 50) \) (if the dog exceeds 50 pounds, it adds $0.80 for each pound over 50)
Now, we can define the piecewise function more formally:
\[
f(x) =
\begin{cases}
20 & \text{if } 0 < x \leq 10 \\
20 + 1.50(x - 10) & \text{if } 10 < x \leq 30 \\
50 + 1.00(x - 30) & \text{if } 30 < x \leq 50 \\
80 + 0.80(x - 50) & \text{if } x > 50
\end{cases}
\]
Make sure to adjust the specific numbers and slopes according to the actual pricing of your dog grooming. Let me know if you'd like further assistance with this!