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Consider this formula for finding the total amount of money generated by an account receiving compound interest: A=200(1+0.08/1...Question
Consider the the formula for finding the total amount of money generated by an account receiving compound interest a = 200 * 1 + 0.08 / 1 when comparing to y = a * 1 + r the general formula for exponential growth which part of the compound interest formula compares best with the variable r
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GPT-4o mini
In the context of your question, let's clarify the two formulas you've provided:
1. The compound interest formula you provided seems to be an incomplete expression. The standard formula for compound interest after one compounding period is typically represented as:
\[ a = P \left(1 + \frac{r}{n}\right)^{nt} \]
where:
- \( a \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( n \) is the number of times that interest is compounded per year.
- \( t \) is the number of years the money is invested or borrowed.
2. The general formula for exponential growth you mentioned is:
\[ y = a \cdot (1 + r) \]
In this context, \( a \) is the initial amount, and \( r \) is the growth rate.
Now, if we focus on the part of the compound interest formula that compares best with the variable \( r \) from the exponential growth formula, we consider the expression inside the parentheses of the compound interest formula.
In the formula:
\[ a = P \left(1 + \frac{r}{n}\right)^{nt} \]
The term \( \frac{r}{n} \) can be related to the growth rate \( r \) in the exponential growth formula, particularly when compounded once per year (\( n = 1 \)). For simplicity, if we assume \( n = 1 \) (annual compounding), then \( r \) from the compound interest formula can be directly compared to \( r \) in the exponential growth formula. In this case:
\[ \frac{r}{1} = r \]
So, when interest is compounded annually, the rate \( r \) in the compound interest formula corresponds directly to the \( r \) in the general exponential growth formula. Therefore, when comparing these, \( r \) in the context of compound interest represents the percentage increase per timeframe.
1. The compound interest formula you provided seems to be an incomplete expression. The standard formula for compound interest after one compounding period is typically represented as:
\[ a = P \left(1 + \frac{r}{n}\right)^{nt} \]
where:
- \( a \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( n \) is the number of times that interest is compounded per year.
- \( t \) is the number of years the money is invested or borrowed.
2. The general formula for exponential growth you mentioned is:
\[ y = a \cdot (1 + r) \]
In this context, \( a \) is the initial amount, and \( r \) is the growth rate.
Now, if we focus on the part of the compound interest formula that compares best with the variable \( r \) from the exponential growth formula, we consider the expression inside the parentheses of the compound interest formula.
In the formula:
\[ a = P \left(1 + \frac{r}{n}\right)^{nt} \]
The term \( \frac{r}{n} \) can be related to the growth rate \( r \) in the exponential growth formula, particularly when compounded once per year (\( n = 1 \)). For simplicity, if we assume \( n = 1 \) (annual compounding), then \( r \) from the compound interest formula can be directly compared to \( r \) in the exponential growth formula. In this case:
\[ \frac{r}{1} = r \]
So, when interest is compounded annually, the rate \( r \) in the compound interest formula corresponds directly to the \( r \) in the general exponential growth formula. Therefore, when comparing these, \( r \) in the context of compound interest represents the percentage increase per timeframe.
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