Find the values of a, b, and c for the quadratic equation below (remember `ax^{2}+bx+c=0`)

3 answers

To determine the values of \( a \), \( b \), and \( c \) for a quadratic equation in the standard form \( ax^{2} + bx + c = 0 \), you would need to provide the specific quadratic equation you want to analyze.

For example, if you have the equation \( 2x^{2} + 3x - 5 = 0 \), then:

  • \( a = 2 \) (the coefficient of \( x^{2} \))
  • \( b = 3 \) (the coefficient of \( x \))
  • \( c = -5 \) (the constant term)

Please provide the specific quadratic equation you have in mind, and I can help you extract the values of \( a \), \( b \), and \( c \).

x^2-7x=4

To express the equation \( x^2 - 7x = 4 \) in standard form \( ax^2 + bx + c = 0 \), we need to move all terms to one side of the equation.

Starting with the given equation:

\[ x^2 - 7x - 4 = 0 \]

Now we can identify the coefficients:

  • \( a = 1 \) (the coefficient of \( x^2 \))
  • \( b = -7 \) (the coefficient of \( x \))
  • \( c = -4 \) (the constant term)

So, for the quadratic equation \( x^2 - 7x - 4 = 0 \):

  • \( a = 1 \)
  • \( b = -7 \)
  • \( c = -4 \)