In order to assess the possible offspring genotypes from a heterozygous orange genotype parent (which could be represented as "Oo", where "O" is orange and "o" is yellow) crossed with parents that are homozygous green (BB) and yellow (BB), we first need to clarify the genotypes involved:
- Let's assume "BB" represents a homozygous dominant trait such as green (since BB usually means homozygous for the dominant trait).
- The heterozygous orange genotype can be represented as "Oo" (where "O" might represent orange and "o" might represent the yellow).
Given these interpretations, we can cross the heterozygous (Oo) with each of the homozygous parents (BB):
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Crossing "Oo" with "BB" (Green):
- Gametes from "Oo": O and o
- Gametes from "BB": B and B
This results in the following possible offspring genotypes:
- OB (Orange-Green)
- oB (Yellow-Green)
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Crossing "Oo" with "BB" (Yellow):
- The cross would be the same as above because we are dealing with the same genotype.
- Again results in:
- OB (Orange-Green)
- oB (Yellow-Green)
Both crosses yield offspring that are either Orange-Green or Yellow-Green. There is no opportunity for producing a Green-Green (BB) genotype in these combinations because neither parent contributes the necessary "B" alleles to create BB offspring from a heterozygous orange.
Thus, if you are crossing a heterozygous orange with BB (either green or yellow), there is 0% chance of producing any offspring with a green (BB) genotype. The offspring will show either the orange or yellow phenotype combined with green due to the presence of the "B" allele, but none will have the genotype for being green (BB) solely. Thus:
Expected percent of offspring with a green (BB) genotype: 0%.