To solve the inequality \( 2(y + 6) \leq 3y \), we can start by distributing the 2 on the left side:
\[ 2y + 12 \leq 3y \]
Next, we can isolate \( y \) by moving the \( 2y \) term to the right side of the inequality:
\[ 12 \leq 3y - 2y \]
This simplifies to:
\[ 12 \leq y \]
or, equivalently,
\[ y \geq 12 \]
Therefore, the solution to the inequality \( 2(y + 6) \leq 3y \) is:
\[ y \geq 12 \]