Question

Current X is 2.5 A and runs for 39 seconds. Current Y is 3.8 A and runs for 24 seconds.

Which current delivered more charge, and how much more charge did it deliver?

X delivered 97.5 C more than Y.
X delivered 6.3 C more than Y.
Y delivered 91.2 C more than X.
Y delivered 1.3 C more than X.

Answer 1

To compare the charges delivered by currents X and Y, we can use the formula for electric charge \( Q \), which is given by:

\[
Q = I \times t
\]

where \( I \) is the current in amperes (A) and \( t \) is the time in seconds (s).

**Calculating charge for current X:**

For current X:
- Current \( I_X = 2.5 \, \text{A} \)
- Time \( t_X = 39 \, \text{s} \)

\[
Q_X = I_X \times t_X = 2.5 \, \text{A} \times 39 \, \text{s} = 97.5 \, \text{C}
\]

**Calculating charge for current Y:**

For current Y:
- Current \( I_Y = 3.8 \, \text{A} \)
- Time \( t_Y = 24 \, \text{s} \)

\[
Q_Y = I_Y \times t_Y = 3.8 \, \text{A} \times 24 \, \text{s} = 91.2 \, \text{C}
\]

**Comparing the charges:**

Current X delivered \( 97.5 \, \text{C} \), and current Y delivered \( 91.2 \, \text{C} \).

Now, let's find out how much more charge X delivered compared to Y:

\[
Q_X - Q_Y = 97.5 \, \text{C} - 91.2 \, \text{C} = 6.3 \, \text{C}
\]

Thus, current X delivered **6.3 C** more than current Y.

The correct answer is:
**X delivered 6.3 C more than Y.**