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In a closed system, three objects have the following momentums: 110 kg⋅m/s , −65 kg⋅m/s , and −100 kg⋅m/s . The objects collide and move together. What is the total momentum after the collision?(1 point) Responses 275 kg⋅m/s 275 kilograms times meters per second −55 kg⋅m/s negative 55 kilograms times meters per second 55 kg⋅m/s 55 kilograms times meters per second −275 kg⋅m/s

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To find the total momentum of the system after the collision, we first need to calculate the total initial momentum by adding the momenta of the three objects:

  1. \( 110 , \text{kg⋅m/s} \)
  2. \( -65 , \text{kg⋅m/s} \)
  3. \( -100 , \text{kg⋅m/s} \)

Now, we can sum these values:

\[ \text{Total Momentum} = 110 + (-65) + (-100) \]

Calculating this step-by-step:

\[ = 110 - 65 - 100 \]

Calculating \( 110 - 65 \):

\[ = 45 \]

Now subtracting \( 100 \):

\[ 45 - 100 = -55 \]

Therefore, the total momentum after the collision is \( -55 , \text{kg⋅m/s} \).

The correct response is: −55 kg⋅m/s.