Question

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Find the value of xxx if A=2x, B=2x+10A=2x,\ B=2x+10A=2x, B=2x+10 and C=1x+8C=1x+8C=1x+8



x=x=x=

Answer 1

To find the value of \( x \) based on the equations given:

1. **First equation**: \( A = 2x \)
2. **Second equation**: \( B = 2x + 10 \)
3. **Third equation**: \( C = 1x + 8 \)

We can substitute for \( A \), \( B \), and \( C \) in terms of \( x \).

So we have:
- \( A = 2x \)
- \( B = 2x + 10 \)
- \( C = x + 8 \)

Let's assume that \( A + B + C = 180^\circ \) if we are dealing with a triangle (it wasn't specified in the problem). Then we can write the equation:

\[
A + B + C = 180
\]
Substituting the values of \( A \), \( B \), and \( C \):

\[
2x + (2x + 10) + (x + 8) = 180
\]

Now, let's simplify this equation:

\[
2x + 2x + 10 + x + 8 = 180
\]

Combine like terms:

\[
(2x + 2x + x) + (10 + 8) = 180
\]
\[
5x + 18 = 180
\]

Next, isolate \( x \):

\[
5x = 180 - 18
\]
\[
5x = 162
\]

Now, divide both sides by 5:

\[
x = \frac{162}{5} = 32.4
\]

Thus, the value of \( x \) is:

\[
\boxed{32.4}
\]