Question
In an experiment, objects 1 and 2 with masses
m
1
and
m
2
, respectively, collide with each other.The objects have initial velocities
v
1
i
and
v
2
i
and final velocities
v
1
f
and
v
2
f
, respectively. Whichresult would prove conservation of momentum?
(1 point)
m1v1i + m1v1f = m2v2i + m2v2f
m1v1i + m2v2i + m1v1f + m2v2f > 0
m1v1i + m2v2i + m1v1f + m2v2f = 0
m1v1i + m2v2i = m1v1f + m2v2f
m
1
and
m
2
, respectively, collide with each other.The objects have initial velocities
v
1
i
and
v
2
i
and final velocities
v
1
f
and
v
2
f
, respectively. Whichresult would prove conservation of momentum?
(1 point)
m1v1i + m1v1f = m2v2i + m2v2f
m1v1i + m2v2i + m1v1f + m2v2f > 0
m1v1i + m2v2i + m1v1f + m2v2f = 0
m1v1i + m2v2i = m1v1f + m2v2f
Answers
GPT-4o mini
The correct equation that would prove the conservation of momentum in a collision is:
**m1v1i + m2v2i = m1v1f + m2v2f**
This equation states that the total momentum before the collision (left side) is equal to the total momentum after the collision (right side), which is the principle of conservation of momentum.
**m1v1i + m2v2i = m1v1f + m2v2f**
This equation states that the total momentum before the collision (left side) is equal to the total momentum after the collision (right side), which is the principle of conservation of momentum.
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