To find the x and y-intercepts of the equation \(10x + 3y = 90\), we can follow these steps:
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To find the x-intercept, set \(y = 0\) and solve for \(x\): \[ 10x + 3(0) = 90 \implies 10x = 90 \implies x = \frac{90}{10} = 9 \] So, the x-intercept is \((9, 0)\).
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To find the y-intercept, set \(x = 0\) and solve for \(y\): \[ 10(0) + 3y = 90 \implies 3y = 90 \implies y = \frac{90}{3} = 30 \] So, the y-intercept is \((0, 30)\).
Thus, the correct x and y-intercepts are:
- The x-intercept is \((9, 0)\)
- The y-intercept is \((0, 30)\)
So, the first option you provided is correct.