To model the relationship between the number of meals dispensed \(x\) and the amount of pet food remaining \(y\), we will first look at the data points provided:
- When \(x = 1\), \(y = 21\)
- When \(x = 3\), \(y = 15\)
- When \(x = 6\), \(y = 6\)
- When \(x = 7\), \(y = 3\)
Next, we can observe how the amount of pet food decreases as the number of meals dispensed increases:
- From \(x = 1\) to \(x = 3\), \(y\) decreases from 21 to 15. (Decrease of 6 cups over 2 meals)
- From \(x = 3\) to \(x = 6\), \(y\) decreases from 15 to 6. (Decrease of 9 cups over 3 meals)
- From \(x = 6\) to \(x = 7\), \(y\) decreases from 6 to 3. (Decrease of 3 cups over 1 meal)
Now we can find the rate at which food is dispensed per meal.
Checking the changes, we find:
- From the first two points, it looks like:
- \(21 - 15 = 6\) cups dispensed over 2 meals → \(6/2 = 3\) cups per meal.
- Between the meals dispensed at \(x = 3\) and \(x = 6\):
- \(15 - 6 = 9\) cups dispensed over 3 meals → \(9/3 = 3\) cups per meal.
- For the last point, from \(x = 6\) to \(x = 7\):
- \(6 - 3 = 3\) cups dispensed over 1 meal → \(3/1 = 3\) cups per meal.
Consistency suggests that the feeder dispenses a fixed amount of 3 cups of food per meal.
Now we can derive the linear function based on the relationship we have observed: The initial amount of food is 21 cups, and we have established that for each meal dispensed, 3 cups are used.
Thus, we can express the function as: \[ y = 21 - 3x \]
Where:
- \(y\) is the amount of pet food remaining,
- \(x\) is the number of meals dispensed.
This function can be used to determine the remaining pet food for any number of meals dispensed.