Use the image to answer the question.

An illustration shows quadrant one of a coordinate plane where the x-axis and y-axis range from 0 to 6 in increments of 1. The y-axis is titled total cost in dollars and the x-axis is titled number of markers. A solid line, labeled A, is marked on the graph and passes through coordinates left parenthesis 0 comma 0 right parenthesis and left parenthesis 3 comma 6 right parenthesis. A dotted line, labeled B, passes through coordinates left parenthesis 0 comma 0 right parenthesis and left parenthesis 6 comma 3 right parenthesis.

Predict what the total cost would be for buying 10 of the type A markers.

(1 point)
Responses

$5.00
$5.00

$2.00
$2.00

$0.50
$0.50

$20.00

1 answer

To determine the total cost for buying 10 of the type A markers based on the provided information, we can first analyze the line labeled A on the graph.

The coordinates given for line A are \( (0, 0) \) and \( (3, 6) \). This indicates that the cost for buying 3 markers is $6.

To find the cost per marker, we can perform the following calculation:

\[ \text{Cost per marker} = \frac{\text{Total cost}}{\text{Number of markers}} = \frac{6}{3} = 2 \text{ dollars per marker} \]

Now, to find the total cost for 10 type A markers, we can multiply the cost per marker by the number of markers:

\[ \text{Total cost for 10 markers} = \text{Cost per marker} \times \text{Number of markers} = 2 \times 10 = 20 \text{ dollars} \]

Therefore, the total cost for buying 10 of the type A markers would be $20.00.

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