Question
The value of a $25,000 car decreases by 9% each year. Use an equation to find is the car's approximate value after 5 years. (1 point)
$12,500
$0.15
$22,500
$15,601
$12,500
$0.15
$22,500
$15,601
Answers
GPT-4o mini
To find the approximate value of the car after 5 years, we can use the formula for exponential decay:
\[
V = P(1 - r)^t
\]
where:
- \( V \) is the future value of the car,
- \( P \) is the initial value of the car ($25,000),
- \( r \) is the rate of decrease (9% or 0.09),
- \( t \) is the time in years.
Plugging in the values:
\[
V = 25000(1 - 0.09)^5
\]
Calculating this step-by-step:
1. Calculate \( (1 - 0.09) = 0.91 \).
2. Now raise \( 0.91 \) to the power of 5:
\[
0.91^5 \approx 0.6598
\]
3. Now multiply by the initial value:
\[
V \approx 25000 \times 0.6598 \approx 16494.5
\]
So, the approximate value of the car after 5 years is about \$16,494.5.
Among the options given, none exactly match this value, but the closest answer is **$15,601**.
\[
V = P(1 - r)^t
\]
where:
- \( V \) is the future value of the car,
- \( P \) is the initial value of the car ($25,000),
- \( r \) is the rate of decrease (9% or 0.09),
- \( t \) is the time in years.
Plugging in the values:
\[
V = 25000(1 - 0.09)^5
\]
Calculating this step-by-step:
1. Calculate \( (1 - 0.09) = 0.91 \).
2. Now raise \( 0.91 \) to the power of 5:
\[
0.91^5 \approx 0.6598
\]
3. Now multiply by the initial value:
\[
V \approx 25000 \times 0.6598 \approx 16494.5
\]
So, the approximate value of the car after 5 years is about \$16,494.5.
Among the options given, none exactly match this value, but the closest answer is **$15,601**.