Question
The table shows the results of a survey in which 10th-grade students were asked how many siblings (brothers and/or sisters) they have.
A 2-column table has 4 rows. The first column is labeled Number of siblings with entries 0, 1, 2, 3. The second column is labeled number of students with entries 4, 18, 10, 8.
What is the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings? Round to the nearest whole percent.
65%
70%
75%
80%
A 2-column table has 4 rows. The first column is labeled Number of siblings with entries 0, 1, 2, 3. The second column is labeled number of students with entries 4, 18, 10, 8.
What is the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings? Round to the nearest whole percent.
65%
70%
75%
80%
Answers
GPT-4o mini
To calculate the experimental probability that a randomly chosen 10th-grade student has at least one, but no more than two siblings, we first need to determine the total number of students surveyed and the number of students who fall within the specified range (1 or 2 siblings).
From the table:
- Number of siblings:
- 0 siblings: 4 students
- 1 sibling: 18 students
- 2 siblings: 10 students
- 3 siblings: 8 students
Now, we can find the total number of students:
\[
\text{Total students} = 4 + 18 + 10 + 8 = 40
\]
Next, we find the number of students with at least one but no more than two siblings:
- Students with 1 sibling: 18
- Students with 2 siblings: 10
Adding these together gives us:
\[
\text{Students with at least 1 and no more than 2 siblings} = 18 + 10 = 28
\]
Now, we can calculate the experimental probability:
\[
\text{Experimental probability} = \frac{\text{Number of students with 1 or 2 siblings}}{\text{Total number of students}} = \frac{28}{40} = 0.7
\]
To express this as a percentage, we multiply by 100:
\[
0.7 \times 100 = 70\%
\]
Thus, the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings is \( \boxed{70\%} \).
From the table:
- Number of siblings:
- 0 siblings: 4 students
- 1 sibling: 18 students
- 2 siblings: 10 students
- 3 siblings: 8 students
Now, we can find the total number of students:
\[
\text{Total students} = 4 + 18 + 10 + 8 = 40
\]
Next, we find the number of students with at least one but no more than two siblings:
- Students with 1 sibling: 18
- Students with 2 siblings: 10
Adding these together gives us:
\[
\text{Students with at least 1 and no more than 2 siblings} = 18 + 10 = 28
\]
Now, we can calculate the experimental probability:
\[
\text{Experimental probability} = \frac{\text{Number of students with 1 or 2 siblings}}{\text{Total number of students}} = \frac{28}{40} = 0.7
\]
To express this as a percentage, we multiply by 100:
\[
0.7 \times 100 = 70\%
\]
Thus, the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings is \( \boxed{70\%} \).