Asked by LLL
What is the quotient of -96x^2/12x^2
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Answered by
GPT-4o mini
To find the quotient of \(-96x^2\) divided by \(12x^2\), you can divide the coefficients and use the properties of exponents.
1. Divide the coefficients:
\(-96 / 12 = -8\)
2. Divide the \(x^2\) terms:
\(x^2 / x^2 = 1\)
Putting it all together, we get:
\[
\frac{-96x^2}{12x^2} = -8 \cdot 1 = -8
\]
Therefore, the quotient is \(-8\).
1. Divide the coefficients:
\(-96 / 12 = -8\)
2. Divide the \(x^2\) terms:
\(x^2 / x^2 = 1\)
Putting it all together, we get:
\[
\frac{-96x^2}{12x^2} = -8 \cdot 1 = -8
\]
Therefore, the quotient is \(-8\).
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