Question

Question 25
Given the following nuclear reaction:





Column A
1.
What is the atomic mass of the new atom?:
What is the atomic mass of the new atom?
2.
What is the atomic number of the new atom?:
What is the atomic number of the new atom?
3.
What is the symbol of the new atom?:
What is the symbol of the new atom?
4.
What type of decay is demonstrated here?:
What type of decay is demonstrated here?
Column B
Column B
a.Alpha Decay
b.86
c.223
d.89
e.Ac
f.Ra
g.Gamma Decay
h.88
i.87
j.222
k.224
l.Fr
m.Beta Decay

Reaction:223/87 Fr ---> 0/-1 e + A/Z X

Answer 1

To analyze the nuclear reaction given ( \( {}^{223}_{87} \text{Fr} \rightarrow {}^{0}_{-1} \text{e} + {}^{A}_{Z} \text{X} \) ), we can determine the attributes of the resulting atom \( \text{X} \) based on the information provided.

1. **Atomic Mass of the New Atom (X)**:
- The original atom, Francium (Fr), has a mass number of 223. An electron (beta particle) emitted has a mass number of 0.
- The mass number of the new atom is thus:
\[
A = 223 - 0 = 223
\]
- **Answer**: \( c.223 \)

2. **Atomic Number of the New Atom (X)**:
- The original atomic number of Francium (Fr) is 87. When a beta particle is emitted, the atomic number decreases by 1 (since a neutron is converted into a proton and an electron).
- Therefore, the atomic number of the new atom is:
\[
Z = 87 - 1 = 86
\]
- **Answer**: \( b.86 \)

3. **Symbol of the New Atom (X)**:
- The new atom after beta decay with atomic number 86 is Radon (Rn).
- The symbol is thus:
- **Answer**: \( \text{Rn} \)

4. **Type of Decay Demonstrated Here**:
- The transformation of a neutron into a proton with the emission of an electron is characteristic of **beta decay**.
- **Answer**: \( m. \text{Beta Decay} \)

Now, compiling the answers:

- **1.** c. 223
- **2.** b. 86
- **3.** Rn (note that this option wasn't in Column B; traditionally, it would be paired with other relevant options)
- **4.** m. Beta Decay