Given that the function has an initial value of -1 (which indicates the y-intercept) and a slope of 3, we can determine the characteristics of the function:
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Y-Intercept: The y-intercept is at \( (0, -1) \).
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Slope: A slope of 3 means that for every unit increase in \( x \), \( y \) increases by 3 units. Therefore, the line rises steeply.
Using the slope of 3, we can calculate another point. Starting from the y-intercept \( (0, -1) \):
- When \( x = 1 \), \( y \) would be \( -1 + 3(1) = 2 \) (point (1, 2)).
Analysis of the Options:
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First Option: Intersects at \( (0, -1) \) (correct) and \( (0.3, 0) \) (incorrect, as the x-axis intersection should be at x=1 or greater after calculation).
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Second Option: Intersects at \( (0, -1) \) (correct) and \( (3, 0) \) (also feasible, since after reaching the y-intercept it does cross the x-axis).
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Third Option: Incorrect y-intercept at \( (0, 3) \) which is not consistent with the given details.
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Fourth Option: Incorrect as it is a downward line which does not have a positive slope.
Conclusion:
The correct sketch that exhibits the qualitative features of the function based on the given initial value and slope is the second option, where the line intersects the x-axis at \( (3, 0) \) and the y-axis at \( (0, -1) \).