Question

A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to accelerate across the ice. If drag and the friction from the ice apply a force of 5 N on the boy, what is the magnitude of the net force acting on him?(1 point) Responses 80 N 80 N 370 N 370 N 70 N 70 N 380 N

Answer 1

To find the net force acting on the boy, we can use the following equation:

$$\text{Net Force}=\text{Applied Forces}-\text{Friction/Drag Forces}$$

1. The boy exerts a force of 300 N.
2. His friend pulls him with a force of 75 N.
3. The drag and friction force amounts to 5 N.

Now, let's calculate the total applied force:

$$\text{Total Applied Force}=300,\text{N}+75,\text{N}=375,\text{N}$$

Next, we subtract the friction and drag force:

$$\text{Net Force}=375,\text{N}-5,\text{N}=370,\text{N}$$

Thus, the magnitude of the net force acting on the boy is 370 N.