To analyze the function \( y = x^2 - 8x \), we can find the key points:
-
Vertex: The vertex of a quadratic function in the form \( y = ax^2 + bx + c \) can be found using the formula \( x = -\frac{b}{2a} \). Here, \( a = 1 \) and \( b = -8 \).
\[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \]
To find the y-coordinate of the vertex, we substitute \( x = 4 \) back into the original equation:
\[ y = (4)^2 - 8(4) = 16 - 32 = -16 \]
So the vertex is at \( (4, -16) \).
-
X-intercepts: To find the x-intercepts, set \( y = 0 \):
\[ 0 = x^2 - 8x \]
Factor the equation:
\[ 0 = x(x - 8) \]
The solutions are \( x = 0 \) and \( x = 8 \). Therefore, the x-intercepts are \( (0, 0) \) and \( (8, 0) \).
-
Y-intercept: To find the y-intercept, set \( x = 0 \):
\[ y = (0)^2 - 8(0) = 0 \]
So the y-intercept is \( (0, 0) \).
Summary of Key Points:
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)
Conclusion:
The correct option from the choices provided is:
- x-intercepts: \( (0, 0) \) and \( (8, 0) \)
- y-intercept: \( (0, 0) \)
- vertex: \( (4, -16) \)