Identify the vertex of y=−10(x+15)2−18

Question

.(1 point)
Responses

(−15,−18)
left parenthesis negative 15 comma negative 18 right parenthesis

(−10,−15)
left parenthesis negative 10 comma negative 15 right parenthesis

(15,−18)
left parenthesis 15 comma negative 18 right parenthesis

(−150,−18)

Answer 1

To identify the vertex of the quadratic function \( y = -10(x + 15)^2 - 18 \), we can observe that the function is in vertex form, which is:

\[ y = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola.

In your equation:

\[ y = -10(x + 15)^2 - 18 \]

we can rewrite it as:

\[ y = -10(x - (-15))^2 - 18 \]

From this, we see that:

• \(h = -15\) (the value that makes the expression zero),
• \(k = -18\) (the constant term).

Therefore, the vertex is at the point:

\((-15, -18)\).

Thus, the correct response is:

(−15, −18).