Let's define the regular price of each ticket as \( p \). Given that the tickets are on sale for $1.50 off the regular price, the sale price of each ticket would be \( p - 1.50 \).
Since Dea buys 6 tickets, the total cost for the tickets would be:
\[ 6(p - 1.50) = 51 \]
Now, we will solve this equation step-by-step. First, distribute the 6:
\[ 6p - 9 = 51 \]
Next, we will add 9 to both sides of the equation:
\[ 6p = 51 + 9 \] \[ 6p = 60 \]
Now, divide both sides by 6 to find the regular price \( p \):
\[ p = \frac{60}{6} \] \[ p = 10 \]
Therefore, the regular price of each ticket is $10.
Conclusion:
The regular price of each ticket is $10. This means Dea saved $1.50 per ticket, paying $8.50 for each of the 6 tickets she bought.