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Tickets to the baseball game are on sale for $1.50 off the regular price. Dea buys 6 tickets. If her total cost is $51, what is...Asked by 🧋🧋life
Tickets to the baseball game are on sale for $1.50 off the regular price. Dea buys 6 tickets. If her total cost is $51, what is the regular price of each ticket? Write and solve an equation of the form p(x±q)=r . Then write a sentence to explain your answer.
Pls be right bot
Pls be right bot
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Answered by
🧋🧋life
Ok write everything you just explained to me and put it into a paragraph
Answered by
GPT-4o mini
Let's define the regular price of each ticket as \( p \). Given that the tickets are on sale for $1.50 off the regular price, the sale price of each ticket would be \( p - 1.50 \).
Since Dea buys 6 tickets, the total cost for the tickets would be:
\[
6(p - 1.50) = 51
\]
Now, we will solve this equation step-by-step. First, distribute the 6:
\[
6p - 9 = 51
\]
Next, we will add 9 to both sides of the equation:
\[
6p = 51 + 9
\]
\[
6p = 60
\]
Now, divide both sides by 6 to find the regular price \( p \):
\[
p = \frac{60}{6}
\]
\[
p = 10
\]
Therefore, the regular price of each ticket is $10.
### Conclusion:
The regular price of each ticket is $10. This means Dea saved $1.50 per ticket, paying $8.50 for each of the 6 tickets she bought.
Since Dea buys 6 tickets, the total cost for the tickets would be:
\[
6(p - 1.50) = 51
\]
Now, we will solve this equation step-by-step. First, distribute the 6:
\[
6p - 9 = 51
\]
Next, we will add 9 to both sides of the equation:
\[
6p = 51 + 9
\]
\[
6p = 60
\]
Now, divide both sides by 6 to find the regular price \( p \):
\[
p = \frac{60}{6}
\]
\[
p = 10
\]
Therefore, the regular price of each ticket is $10.
### Conclusion:
The regular price of each ticket is $10. This means Dea saved $1.50 per ticket, paying $8.50 for each of the 6 tickets she bought.
Answered by
GPT-4o mini
To determine the regular price of each baseball ticket, we let \( p \) represent the regular price. The tickets are on sale for $1.50 off, so the sale price becomes \( p - 1.50 \). Since Dea purchased 6 tickets for a total cost of $51, we can set up the equation: \( 6(p - 1.50) = 51 \). Upon expanding and simplifying this equation, we first distribute the 6 to get \( 6p - 9 = 51 \). By adding 9 to both sides, we obtain \( 6p = 60 \). Dividing both sides by 6 gives us \( p = 10 \). Therefore, the regular price of each ticket is $10. This indicates that Dea saved $1.50 per ticket, resulting in a sale price of $8.50 for each of the 6 tickets she purchased.
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