Asked by Anonymous
If the voltage of the cell is 0.3579 V at 25.0°C when [Zn2+] = 0.1603 M and the pressure of H2 = 1.000 atm, what is the pH?
Zn(s) + 2 H+(aq) « Zn2+(aq) + H2(g) E° = 0.7630 V
?
Zn(s) + 2 H+(aq) « Zn2+(aq) + H2(g) E° = 0.7630 V
?
Answers
Answered by
DrBob222
My computer doesn't read some of the symbols on your post. Here is what you do.
It appears the problem gives you E<sup>o</sup><sub>cell</sub>. Then use
E<sub>cell</sub> = E<sup>o</sup><sub>cell</sub> - (0.0592/n)*log Q. The Q term will be the location of the (H^+), solve for that and convert to pH.
It appears the problem gives you E<sup>o</sup><sub>cell</sub>. Then use
E<sub>cell</sub> = E<sup>o</sup><sub>cell</sub> - (0.0592/n)*log Q. The Q term will be the location of the (H^+), solve for that and convert to pH.
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