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Rewrite the function by completing the square. \[f(x)=x^{2}-12x-29\] \[f(x)=(x+\] \[)^2+\]Question
Rewrite the function by completing the square.
\[f(x)=x^{2}+12x-69\]
\[f(x)=(x+\]
\[)^2+\]
\[f(x)=x^{2}+12x-69\]
\[f(x)=(x+\]
\[)^2+\]
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Answered by
GPT-4o mini
To rewrite the function \( f(x) = x^2 + 12x - 69 \) by completing the square, follow these steps:
1. Start with the quadratic part of the function, which is \( x^2 + 12x \).
2. To complete the square, take the coefficient of \( x \) (which is 12), divide it by 2, and square the result:
\[
\left(\frac{12}{2}\right)^2 = 6^2 = 36
\]
3. Rewrite the quadratic expression by adding and subtracting this square:
\[
x^2 + 12x = (x^2 + 12x + 36) - 36 = (x + 6)^2 - 36
\]
4. Substitute this back into \( f(x) \):
\[
f(x) = (x + 6)^2 - 36 - 69
\]
5. Combine the constant terms:
\[
-36 - 69 = -105
\]
6. Thus, the function can be rewritten as:
\[
f(x) = (x + 6)^2 - 105
\]
So the final answer is:
\[
f(x) = (x + 6)^2 - 105
\]
1. Start with the quadratic part of the function, which is \( x^2 + 12x \).
2. To complete the square, take the coefficient of \( x \) (which is 12), divide it by 2, and square the result:
\[
\left(\frac{12}{2}\right)^2 = 6^2 = 36
\]
3. Rewrite the quadratic expression by adding and subtracting this square:
\[
x^2 + 12x = (x^2 + 12x + 36) - 36 = (x + 6)^2 - 36
\]
4. Substitute this back into \( f(x) \):
\[
f(x) = (x + 6)^2 - 36 - 69
\]
5. Combine the constant terms:
\[
-36 - 69 = -105
\]
6. Thus, the function can be rewritten as:
\[
f(x) = (x + 6)^2 - 105
\]
So the final answer is:
\[
f(x) = (x + 6)^2 - 105
\]
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