Question

Slice of Pizza is $3.20 and a drink is $1. U spent $10.60. Write and solve an equation " p" number of slices of pizza u brought.

Answer 1

Let \( p \) represent the number of slices of pizza you bought.

The cost of \( p \) slices of pizza would be \( 3.20p \). Since a drink costs $1, if you bought \( d \) drinks, the cost for drinks would be \( 1d \) or simply \( d \).

The total amount spent was $10.60, so we can write the equation:

\[
3.20p + d = 10.60
\]

To solve this equation, we need to express \( d \) in terms of \( p \) or find a specific number of drinks. Since drinks are typically purchased in whole numbers, we can rearrange the equation to find \( d \):

\[
d = 10.60 - 3.20p
\]

Now, since \( d \) must be a non-negative whole number, the right side of the equation must also be a non-negative whole number. This implies:

\[
10.60 - 3.20p \geq 0
\]
\[
10.60 \geq 3.20p
\]
\[
\frac{10.60}{3.20} \geq p
\]
\[
3.3125 \geq p
\]

Thus, the maximum integer value for \( p \) is 3. We will check whole numbers of slices (0, 1, 2, 3) to determine valid pairs of \( (p, d) \):

1. **If \( p = 0 \)**:
\[
d = 10.60 - 3.20(0) = 10.60 \quad (not an integer)
\]

2. **If \( p = 1 \)**:
\[
d = 10.60 - 3.20(1) = 10.60 - 3.20 = 7.40 \quad (not an integer)
\]

3. **If \( p = 2 \)**:
\[
d = 10.60 - 3.20(2) = 10.60 - 6.40 = 4.20 \quad (not an integer)
\]

4. **If \( p = 3 \)**:
\[
d = 10.60 - 3.20(3) = 10.60 - 9.60 = 1.00 \quad (valid)
\]

Based on these calculations, the only valid solution is \( p = 3 \) slices of pizza and \( d = 1 \) drink.

Therefore, you bought **3 slices of pizza** and **1 drink**.