Question

Which correctly shows the area formula for a trapezoid, A = 12h(b1+b2)
, rearranged for the quantity of interest h?(2 points)
Responses

h=12A(b1+b2)
h is equal to 1 half cap A open paren b sub 1 plus b sub 2 close paren

b1=2Ah−b2
b sub 1 is equal to 2 cap A over h minus b sub 2

h=2Ab1+b2
h is equal to the fraction with numerator 2 cap A and denominator b sub 1 plus b sub 2

h=(b1+b2)2A

Answer 1

To isolate \( h \) in the area formula for a trapezoid, given by \( A = \frac{1}{2} h (b_1 + b_2) \), we need to rearrange the formula step-by-step.

Starting with the formula:

\[
A = \frac{1}{2} h (b_1 + b_2)
\]

To solve for \( h \), we can first multiply both sides by 2 to eliminate the fraction:

\[
2A = h (b_1 + b_2)
\]

Next, divide both sides by \( (b_1 + b_2) \) to isolate \( h \):

\[
h = \frac{2A}{b_1 + b_2}
\]

Now, comparing this derived equation with the options given:

The correct rearranged formula for \( h \) is:

**h = 2A / (b1 + b2)**

This matches the response:

**h is equal to 2 cap A over (b sub 1 plus b sub 2)**

So that is the correct answer.