Question
find the volume of the cylinder - use 3.14 for pi. 8 cm, 3 cm, 6 cm.
Answers
Answer
a jar of peanut butter has a height of 16 centimeters and a width of 10 centimeters. find the volume of the peanut butter jar. use 3.14 for pi.
Answer
a jar of salsa has a height of 6 inches and a radius of 2 inches. find the volume of the salsa jar. use 3.14 for pi.
Answer
a water tower has a height of 25 meters and a width of 16 meters. what is the volume of the water tower? use 3.14 for pi.
Answered by
GPT-4o mini
To find the volume of a cylinder, you can use the formula:
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the dimensions you provided, we need to determine which measurement is the radius and which is the height. For a cylinder, the radius should be half of the diameter.
If we assume:
- The diameter is 8 cm, then the radius \( r = \frac{8}{2} = 4 \) cm
- The height \( h = 6 \) cm
Now, we can calculate the volume:
\[
V = 3.14 \times (4)^2 \times 6
\]
Calculating \( (4)^2 \):
\[
(4)^2 = 16
\]
Now substituting back into the volume equation:
\[
V = 3.14 \times 16 \times 6
\]
Calculating \( 16 \times 6 \):
\[
16 \times 6 = 96
\]
Now substituting that in:
\[
V = 3.14 \times 96
\]
Calculating \( 3.14 \times 96 \):
\[
V = 301.44 \, \text{cm}^3
\]
Thus, the volume of the cylinder is approximately \( 301.44 \, \text{cm}^3 \).
\[
V = \pi r^2 h
\]
where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the dimensions you provided, we need to determine which measurement is the radius and which is the height. For a cylinder, the radius should be half of the diameter.
If we assume:
- The diameter is 8 cm, then the radius \( r = \frac{8}{2} = 4 \) cm
- The height \( h = 6 \) cm
Now, we can calculate the volume:
\[
V = 3.14 \times (4)^2 \times 6
\]
Calculating \( (4)^2 \):
\[
(4)^2 = 16
\]
Now substituting back into the volume equation:
\[
V = 3.14 \times 16 \times 6
\]
Calculating \( 16 \times 6 \):
\[
16 \times 6 = 96
\]
Now substituting that in:
\[
V = 3.14 \times 96
\]
Calculating \( 3.14 \times 96 \):
\[
V = 301.44 \, \text{cm}^3
\]
Thus, the volume of the cylinder is approximately \( 301.44 \, \text{cm}^3 \).
Answered by
GPT-4o mini
To find the volume of a jar of peanut butter, we can assume that the jar is in the shape of a cylinder. The formula for the volume \( V \) of a cylinder is:
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information you provided:
- The height \( h = 16 \) cm
- The width of the jar (diameter) is \( 10 \) cm. Therefore, the radius \( r \) is half of the width:
\[
r = \frac{10}{2} = 5 \, \text{cm}
\]
Now we can plug in the values into the volume formula:
\[
V = 3.14 \times (5)^2 \times 16
\]
Calculating \( (5)^2 \):
\[
(5)^2 = 25
\]
Now substituting back into the volume equation:
\[
V = 3.14 \times 25 \times 16
\]
Calculating \( 25 \times 16 \):
\[
25 \times 16 = 400
\]
Now substituting that in:
\[
V = 3.14 \times 400
\]
Calculating \( 3.14 \times 400 \):
\[
V = 1256 \, \text{cm}^3
\]
So, the volume of the peanut butter jar is approximately \( 1256 \, \text{cm}^3 \).
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information you provided:
- The height \( h = 16 \) cm
- The width of the jar (diameter) is \( 10 \) cm. Therefore, the radius \( r \) is half of the width:
\[
r = \frac{10}{2} = 5 \, \text{cm}
\]
Now we can plug in the values into the volume formula:
\[
V = 3.14 \times (5)^2 \times 16
\]
Calculating \( (5)^2 \):
\[
(5)^2 = 25
\]
Now substituting back into the volume equation:
\[
V = 3.14 \times 25 \times 16
\]
Calculating \( 25 \times 16 \):
\[
25 \times 16 = 400
\]
Now substituting that in:
\[
V = 3.14 \times 400
\]
Calculating \( 3.14 \times 400 \):
\[
V = 1256 \, \text{cm}^3
\]
So, the volume of the peanut butter jar is approximately \( 1256 \, \text{cm}^3 \).
Answered by
GPT-4o mini
To find the volume of the salsa jar, which we can assume is in the shape of a cylinder, we use the formula:
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information you provided:
- The height \( h = 6 \) inches
- The radius \( r = 2 \) inches
Now we can plug in the values into the volume formula:
\[
V = 3.14 \times (2)^2 \times 6
\]
Calculating \( (2)^2 \):
\[
(2)^2 = 4
\]
Now substituting that back into the volume equation:
\[
V = 3.14 \times 4 \times 6
\]
Calculating \( 4 \times 6 \):
\[
4 \times 6 = 24
\]
Now substituting that in:
\[
V = 3.14 \times 24
\]
Calculating \( 3.14 \times 24 \):
\[
V = 75.36 \, \text{in}^3
\]
So, the volume of the salsa jar is approximately \( 75.36 \, \text{in}^3 \).
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information you provided:
- The height \( h = 6 \) inches
- The radius \( r = 2 \) inches
Now we can plug in the values into the volume formula:
\[
V = 3.14 \times (2)^2 \times 6
\]
Calculating \( (2)^2 \):
\[
(2)^2 = 4
\]
Now substituting that back into the volume equation:
\[
V = 3.14 \times 4 \times 6
\]
Calculating \( 4 \times 6 \):
\[
4 \times 6 = 24
\]
Now substituting that in:
\[
V = 3.14 \times 24
\]
Calculating \( 3.14 \times 24 \):
\[
V = 75.36 \, \text{in}^3
\]
So, the volume of the salsa jar is approximately \( 75.36 \, \text{in}^3 \).
Answered by
GPT-4o mini
To find the volume of the water tower, we can assume it has the shape of a cylinder. The formula for the volume \( V \) of a cylinder is given by:
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information you provided:
- The height \( h = 25 \) meters
- The width of the water tower (which is the diameter) is \( 16 \) meters. Therefore, the radius \( r \) is half of the diameter:
\[
r = \frac{16}{2} = 8 \, \text{meters}
\]
Now we can plug these values into the volume formula:
\[
V = 3.14 \times (8)^2 \times 25
\]
Calculating \( (8)^2 \):
\[
(8)^2 = 64
\]
Now substituting that back into the volume equation:
\[
V = 3.14 \times 64 \times 25
\]
Next, we calculate \( 64 \times 25 \):
\[
64 \times 25 = 1600
\]
Now substituting that in:
\[
V = 3.14 \times 1600
\]
Calculating \( 3.14 \times 1600 \):
\[
V = 5024 \, \text{m}^3
\]
Thus, the volume of the water tower is approximately \( 5024 \, \text{m}^3 \).
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the base of the cylinder,
- \( h \) is the height of the cylinder.
From the information you provided:
- The height \( h = 25 \) meters
- The width of the water tower (which is the diameter) is \( 16 \) meters. Therefore, the radius \( r \) is half of the diameter:
\[
r = \frac{16}{2} = 8 \, \text{meters}
\]
Now we can plug these values into the volume formula:
\[
V = 3.14 \times (8)^2 \times 25
\]
Calculating \( (8)^2 \):
\[
(8)^2 = 64
\]
Now substituting that back into the volume equation:
\[
V = 3.14 \times 64 \times 25
\]
Next, we calculate \( 64 \times 25 \):
\[
64 \times 25 = 1600
\]
Now substituting that in:
\[
V = 3.14 \times 1600
\]
Calculating \( 3.14 \times 1600 \):
\[
V = 5024 \, \text{m}^3
\]
Thus, the volume of the water tower is approximately \( 5024 \, \text{m}^3 \).