To solve the equation \( \frac{8}{9}\left(x + \frac{1}{2}\right) = \frac{32}{3} \), follow these steps:
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Multiply both sides by 9 to eliminate the fraction:
\[ 9 \cdot \frac{8}{9}\left(x + \frac{1}{2}\right) = 9 \cdot \frac{32}{3} \]
This simplifies to:
\[ 8\left(x + \frac{1}{2}\right) = 96 \]
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Distribute the 8 on the left side:
\[ 8x + 4 = 96 \]
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Subtract 4 from both sides:
\[ 8x = 96 - 4 \]
So,
\[ 8x = 92 \]
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Divide both sides by 8:
\[ x = \frac{92}{8} \]
Simplify the fraction:
\[ x = \frac{23}{2} \quad \text{or} \quad x = 11.5 \]
Thus, the solution for \( x \) is:
\[ x = \frac{23}{2} \] or \( x = 11.5 \).