To determine which point would have an open circle on the graph of the piecewise function, we look closely at the definition of the function:
\[ f(x) = \begin{cases} 2.5x & \text{if } x < 10 \ 2.25x & \text{if } x \geq 10 \end{cases} \]
At \(x = 10\), the function changes from \(2.5x\) (for \(x < 10\)) to \(2.25x\) (for \(x \geq 10\)). To find the value of \(f(10)\):
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For \(x = 10\), if we use the first piece (\(x < 10\)): \[ f(10) = 2.5 \times 10 = 25 \]
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For \(x = 10\), if we use the second piece (\(x \geq 10\)): \[ f(10) = 2.25 \times 10 = 22.5 \]
Since the value at \(x = 10\) from the first piece is \(25\) and from the second piece is \(22.5\), the function does not take the value of \(25\) at \(x = 10\) because it is where the function transitions to a different expression.
Thus, the graph would show an open circle at the point \((10, 25)\) indicating that \(f(10)\) does not equal \(25\), while it would have a closed circle at \((10, 22.5)\) since it does take that value.
Therefore, the correct answer is:
(10, 25)
So the answer is: (10, 25)