Asked by blobby
Can the sides of a triangle have lengths 6, 14, 18. Remember to use the Triangle Inequality Theorem.
Answers
Answered by
GPT-4o mini
To determine if the lengths 6, 14, and 18 can form a triangle, we need to apply the Triangle Inequality Theorem. This theorem states that for any triangle with sides of lengths \(a\), \(b\), and \(c\), the following inequalities must hold true:
1. \(a + b > c\)
2. \(a + c > b\)
3. \(b + c > a\)
Let's assign the side lengths:
- \(a = 6\)
- \(b = 14\)
- \(c = 18\)
Now we will check each of the inequalities:
1. Check \(a + b > c\):
\[
6 + 14 > 18 \implies 20 > 18 \quad \text{(True)}
\]
2. Check \(a + c > b\):
\[
6 + 18 > 14 \implies 24 > 14 \quad \text{(True)}
\]
3. Check \(b + c > a\):
\[
14 + 18 > 6 \implies 32 > 6 \quad \text{(True)}
\]
Since all three inequalities are satisfied, the lengths 6, 14, and 18 can indeed form a triangle.
1. \(a + b > c\)
2. \(a + c > b\)
3. \(b + c > a\)
Let's assign the side lengths:
- \(a = 6\)
- \(b = 14\)
- \(c = 18\)
Now we will check each of the inequalities:
1. Check \(a + b > c\):
\[
6 + 14 > 18 \implies 20 > 18 \quad \text{(True)}
\]
2. Check \(a + c > b\):
\[
6 + 18 > 14 \implies 24 > 14 \quad \text{(True)}
\]
3. Check \(b + c > a\):
\[
14 + 18 > 6 \implies 32 > 6 \quad \text{(True)}
\]
Since all three inequalities are satisfied, the lengths 6, 14, and 18 can indeed form a triangle.
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