What are the coordinates of point D’ if quadrilateral ABCD is dilated with scale factor 2/3 and center (0,0)?

D(9,6)

1 answer

To find the coordinates of point \( D' \) after dilating point \( D(9, 6) \) with a scale factor of \( \frac{2}{3} \) and center at the origin \( (0,0) \), we can use the formula for dilation:

\[ D' = \left( k \cdot x, k \cdot y \right) \]

where \( k \) is the scale factor, \( x \) is the x-coordinate of the original point, and \( y \) is the y-coordinate of the original point.

Given:

  • \( k = \frac{2}{3} \)
  • \( D(9, 6) \)

We calculate the coordinates of \( D' \):

\[ D' = \left( \frac{2}{3} \cdot 9, \frac{2}{3} \cdot 6 \right) \]

Calculating the x-coordinate:

\[ \frac{2}{3} \cdot 9 = \frac{18}{3} = 6 \]

Calculating the y-coordinate:

\[ \frac{2}{3} \cdot 6 = \frac{12}{3} = 4 \]

Thus, the coordinates of point \( D' \) are:

\[ D' = (6, 4) \]