Given the sequence find the 25th term

{-1,3,7,11…}
Options
103
99
95
91

1 answer

To find the 25th term of the sequence \(-1, 3, 7, 11, \ldots\), we first need to identify the pattern in the sequence.

The sequence can be analyzed as follows:

  • The first term (\(a_1\)) is \(-1\).
  • The second term (\(a_2\)) is \(3\).
  • The third term (\(a_3\)) is \(7\).
  • The fourth term (\(a_4\)) is \(11\).

We can notice the differences between the consecutive terms:

  • \(3 - (-1) = 4\)
  • \(7 - 3 = 4\)
  • \(11 - 7 = 4\)

The common difference is \(4\). Since this is an arithmetic sequence, we can use the formula for the \(n\)-th term of an arithmetic sequence:

\[ a_n = a_1 + (n-1)d \]

where:

  • \(a_1\) is the first term,
  • \(d\) is the common difference,
  • \(n\) is the term number.

Substituting the known values into the formula:

\[ a_n = -1 + (n-1) \cdot 4 \]

Now, we need to find the 25th term (\(a_{25}\)):

\[ a_{25} = -1 + (25-1) \cdot 4 \] \[ = -1 + 24 \cdot 4 \] \[ = -1 + 96 \] \[ = 95 \]

Thus, the 25th term of the sequence is \(95\).

The correct answer is \(\boxed{95}\).