To find \( m \angle C \) in triangle \( DPZ \), we use the property of the angles in a triangle, which states that the sum of the interior angles in any triangle is \( 180^\circ \).
We are given:
- \( m \angle P = 39^\circ \)
- \( m \angle D = 113^\circ \)
Let's denote \( m \angle C \) as \( x \).
The equation for the sum of the angles in triangle \( DPZ \) can be set up as:
\[ m \angle P + m \angle D + m \angle C = 180^\circ \]
Substituting the known values into the equation:
\[ 39^\circ + 113^\circ + x = 180^\circ \]
Now, add \( 39 \) and \( 113 \):
\[ 152^\circ + x = 180^\circ \]
Next, we can find \( x \) by isolating it:
\[ x = 180^\circ - 152^\circ \]
\[ x = 28^\circ \]
Thus, the measure of angle \( C \) is:
\[ \boxed{28^\circ} \]