Question
△DPZ can be mapped onto triangle, W, V, C△WVC by a reflection. If m, angle, P, equals, 39, degreesm∠P=39
∘
and m, angle, D, equals, 113, degreesm∠D=113
∘
, find m, angle, Cm∠C.
Answer
Attempt 1 out of 2
m, angle, Cm∠C
be determined.
∘
and m, angle, D, equals, 113, degreesm∠D=113
∘
, find m, angle, Cm∠C.
Answer
Attempt 1 out of 2
m, angle, Cm∠C
be determined.
Answers
GPT-4o mini
To find \( m \angle C \) in triangle \( DPZ \), we use the property of the angles in a triangle, which states that the sum of the interior angles in any triangle is \( 180^\circ \).
We are given:
- \( m \angle P = 39^\circ \)
- \( m \angle D = 113^\circ \)
Let's denote \( m \angle C \) as \( x \).
The equation for the sum of the angles in triangle \( DPZ \) can be set up as:
\[
m \angle P + m \angle D + m \angle C = 180^\circ
\]
Substituting the known values into the equation:
\[
39^\circ + 113^\circ + x = 180^\circ
\]
Now, add \( 39 \) and \( 113 \):
\[
152^\circ + x = 180^\circ
\]
Next, we can find \( x \) by isolating it:
\[
x = 180^\circ - 152^\circ
\]
\[
x = 28^\circ
\]
Thus, the measure of angle \( C \) is:
\[
\boxed{28^\circ}
\]
We are given:
- \( m \angle P = 39^\circ \)
- \( m \angle D = 113^\circ \)
Let's denote \( m \angle C \) as \( x \).
The equation for the sum of the angles in triangle \( DPZ \) can be set up as:
\[
m \angle P + m \angle D + m \angle C = 180^\circ
\]
Substituting the known values into the equation:
\[
39^\circ + 113^\circ + x = 180^\circ
\]
Now, add \( 39 \) and \( 113 \):
\[
152^\circ + x = 180^\circ
\]
Next, we can find \( x \) by isolating it:
\[
x = 180^\circ - 152^\circ
\]
\[
x = 28^\circ
\]
Thus, the measure of angle \( C \) is:
\[
\boxed{28^\circ}
\]