Question
Write an equation that represents the “n”th term of the sequence below using the explicit formula an =‘a1+ (n-1)d
{2,-1,-4,-7…)
{2,-1,-4,-7…)
Answers
Answer
Options an = 2n -5
an =3n-1
an =-3n-10
an = -3n + 5
an =3n-1
an =-3n-10
an = -3n + 5
Answered by
GPT-4o mini
To find the \( n \)th term of the sequence \( 2, -1, -4, -7, \ldots \), we first identify the first term \( a_1 \) and the common difference \( d \):
1. The first term \( a_1 \) is \( 2 \).
2. To find the common difference \( d \), we subtract the first term from the second term:
\[
d = -1 - 2 = -3
\]
Now that we have identified \( a_1 = 2 \) and \( d = -3 \), we can use the explicit formula for the \( n \)th term of an arithmetic sequence, which is given by:
\[
a_n = a_1 + (n-1)d
\]
Substituting \( a_1 \) and \( d \) into the formula:
\[
a_n = 2 + (n-1)(-3)
\]
Now, we can simplify this:
\[
a_n = 2 - 3(n-1)
\]
\[
a_n = 2 - 3n + 3
\]
\[
a_n = 5 - 3n
\]
Thus, the explicit formula for the \( n \)th term of the sequence is:
\[
a_n = 5 - 3n
\]
1. The first term \( a_1 \) is \( 2 \).
2. To find the common difference \( d \), we subtract the first term from the second term:
\[
d = -1 - 2 = -3
\]
Now that we have identified \( a_1 = 2 \) and \( d = -3 \), we can use the explicit formula for the \( n \)th term of an arithmetic sequence, which is given by:
\[
a_n = a_1 + (n-1)d
\]
Substituting \( a_1 \) and \( d \) into the formula:
\[
a_n = 2 + (n-1)(-3)
\]
Now, we can simplify this:
\[
a_n = 2 - 3(n-1)
\]
\[
a_n = 2 - 3n + 3
\]
\[
a_n = 5 - 3n
\]
Thus, the explicit formula for the \( n \)th term of the sequence is:
\[
a_n = 5 - 3n
\]
Answered by
GPT-4o mini
To match the given options with our previously derived equation, let's rewrite the formula we derived:
We found:
\[
a_n = 5 - 3n
\]
We can rearrange it to match the options provided:
\[
a_n = -3n + 5
\]
Now let's compare this with the given options:
1. \( a_n = 2n - 5 \)
2. \( a_n = 3n - 1 \)
3. \( a_n = -3n - 10 \)
4. \( a_n = -3n + 5 \)
The correct option that matches our calculations is:
\[
\boxed{a_n = -3n + 5}
\]
We found:
\[
a_n = 5 - 3n
\]
We can rearrange it to match the options provided:
\[
a_n = -3n + 5
\]
Now let's compare this with the given options:
1. \( a_n = 2n - 5 \)
2. \( a_n = 3n - 1 \)
3. \( a_n = -3n - 10 \)
4. \( a_n = -3n + 5 \)
The correct option that matches our calculations is:
\[
\boxed{a_n = -3n + 5}
\]