Question
What type of number will result from multiplying −8–√
and 45
?(1 point)
Responses
a rational number
a rational number
an irrational number
an irrational number
the number zero
the number zero
an integer
and 45
?(1 point)
Responses
a rational number
a rational number
an irrational number
an irrational number
the number zero
the number zero
an integer
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the result of multiplying \(-8 - \sqrt{8}\) and \(45\), we can break it down:
1. \(-8\) is an integer.
2. \(-\sqrt{8}\) is the same as \(-\sqrt{4 \cdot 2} = -2\sqrt{2}\), which is an irrational number.
When you add an integer (-8) and an irrational number (-2√2), the result, \(-8 - 2\sqrt{2}\), is still an irrational number.
Now, when you multiply this entire expression by \(45\):
\[
45(-8 - 2\sqrt{2}) = 45(-8) + 45(-2\sqrt{2})
\]
This simplifies to:
\[
-360 - 90\sqrt{2}
\]
Both terms in this expression contribute to the overall type of the result:
- \(-360\) is a rational number.
- \(-90\sqrt{2}\) is irrational (since \(\sqrt{2}\) is irrational).
When you combine a rational number and an irrational number, the result is generally irrational.
Thus, the final product will be an irrational number.
So the correct response is **an irrational number**.
1. \(-8\) is an integer.
2. \(-\sqrt{8}\) is the same as \(-\sqrt{4 \cdot 2} = -2\sqrt{2}\), which is an irrational number.
When you add an integer (-8) and an irrational number (-2√2), the result, \(-8 - 2\sqrt{2}\), is still an irrational number.
Now, when you multiply this entire expression by \(45\):
\[
45(-8 - 2\sqrt{2}) = 45(-8) + 45(-2\sqrt{2})
\]
This simplifies to:
\[
-360 - 90\sqrt{2}
\]
Both terms in this expression contribute to the overall type of the result:
- \(-360\) is a rational number.
- \(-90\sqrt{2}\) is irrational (since \(\sqrt{2}\) is irrational).
When you combine a rational number and an irrational number, the result is generally irrational.
Thus, the final product will be an irrational number.
So the correct response is **an irrational number**.
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