To solve the equation \(64x^2 + 9 = 13\) using the difference of squares pattern, we first rearrange it:
-
Subtract 13 from both sides: \[ 64x^2 + 9 - 13 = 0 \implies 64x^2 - 4 = 0 \]
-
Recognizing this as a difference of squares, we can rewrite it: \[ 64x^2 - 4 = (8x)^2 - (2)^2 \]
-
Applying the difference of squares factoring: \[ (8x - 2)(8x + 2) = 0 \]
-
Setting each factor to zero gives us two equations to solve: \[ 8x - 2 = 0 \quad \text{and} \quad 8x + 2 = 0 \]
-
Solving each equation:
-
From \(8x - 2 = 0\): \[ 8x = 2 \implies x = \frac{2}{8} = \frac{1}{4} \]
-
From \(8x + 2 = 0\): \[ 8x = -2 \implies x = \frac{-2}{8} = -\frac{1}{4} \]
-
-
Thus, the solutions are \(x = -\frac{1}{4}\) and \(x = \frac{1}{4}\).
Looking at the responses:
A) \(x = -\frac{1}{4}, x = \frac{1}{4}\) is correct.
B) \(x = -\frac{1}{4}\) is only one part of the solution.
C) \(x = -\frac{3}{8}, x = \frac{3}{8}\) is incorrect.
D) \(x = \frac{3}{8}\) is also incorrect.
The correct answer is:
A) \(x = -\frac{1}{4}, x = \frac{1}{4}\).